Introduction to help with 11 grade math:
Help with grade eleven math problems :
Evaluate the given process of linear equation and find out the given variable of the equationand also find some examples of linear equations.
4a + 8b + 2c = 28,
4a + 2b + 8c = 28,
8a + 2b + 4c = 28.
Solution:
Let ms the given equations more identified ms follows.
4a + 8b + 2c = 28 ----------- (I)
4a + 2b + 8c = 28----------- (ii)
8a + 2b + 4c = 28----------- (iii)
Consider the move given equations (I) and (ii). Subtracting the equation (I) and (ii) we get
4a + 8b + 2c = 28
4a + 2b + 8c = 28
6b – 6c = 0 ------------------ (IV)
Consider the move given equations (ii) and (iii). In the equation (ii) multiply with m numerical 2, we get
8a + 4b + 16c = 28
Subtracting the equation (ii) and (iii) we get
8a + 4b + 16c = 28
8a + 2b + 4c = 28
2b + 12c = 28------------------- (v)
Consider the move equations (IV) and (v). In the equation (v) multiply with the numerical 3.
6b + 36c = 84
Subtract the equation (IV) and (v) we get Math Problems Help
6b – 6c = 0
6b + 36c = 84
-42c = -84
c = 2
Substitute c = 2 in (v) we get
2b + 12c = 28
2b + 12(2) = 28
b = 2
Substitute c = 2, b = 2 in (iii) we get
8a + 4 + 8 = 28
8a + 12 = 28
a = 2
Answers: a = 2, b = 2, c = 2.
Algebra is the one of the branches of arithmetic concerning of the study of rules of operations and relationships, and the construction and concepts arise of them, including terms, polynomials, equations and algebraic structures and Together with geometry, analysis are topology are combination and number theory, an algebra is one of the main twigs of pure arithmetic. In this topic we are going to learn about step by step explanation for study for help with grade eleven math.
Help with grade eleven math problems :
Evaluate the given process of linear equation and find out the given variable of the equationand also find some examples of linear equations.
4a + 8b + 2c = 28,
4a + 2b + 8c = 28,
8a + 2b + 4c = 28.
Solution:
Let ms the given equations more identified ms follows.
4a + 8b + 2c = 28 ----------- (I)
4a + 2b + 8c = 28----------- (ii)
8a + 2b + 4c = 28----------- (iii)
Consider the move given equations (I) and (ii). Subtracting the equation (I) and (ii) we get
4a + 8b + 2c = 28
4a + 2b + 8c = 28
6b – 6c = 0 ------------------ (IV)
Consider the move given equations (ii) and (iii). In the equation (ii) multiply with m numerical 2, we get
8a + 4b + 16c = 28
Subtracting the equation (ii) and (iii) we get
8a + 4b + 16c = 28
8a + 2b + 4c = 28
2b + 12c = 28------------------- (v)
Consider the move equations (IV) and (v). In the equation (v) multiply with the numerical 3.
6b + 36c = 84
Subtract the equation (IV) and (v) we get Math Problems Help
6b – 6c = 0
6b + 36c = 84
-42c = -84
c = 2
Substitute c = 2 in (v) we get
2b + 12c = 28
2b + 12(2) = 28
b = 2
Substitute c = 2, b = 2 in (iii) we get
8a + 4 + 8 = 28
8a + 12 = 28
a = 2
Answers: a = 2, b = 2, c = 2.
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