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If the length of the rectangle is increased by 4 inches and the width is decreased by 1 inch, Need geometry problem solver,the area will be 60 square inches. Calculate the original dimensions of the rectangle if a rectangle is 4 times as long as it is wide.

a) 4 in, 16 in
b) 12 in, 48 in
c) 3 in, 12 in
d) None of the above

Answer: Let x = original width of rectangle

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A = lw
60 = (4x + 4)(x –1)
60 = 4x2 – 4x + 4x – 4
4x2 – 4 – 60 = 0
4x2 – 64 = 0
(2x)2 – (8)2 = 0
(2x)2 – (8)2 = 0
(2x – 8)(2x + 8) = 0
We get two values for x.

Since x is a dimension,Need free geometry homework help it would be positive.
So, we take x = 4. The question requires the dimensions of the original rectangle.
The width of the original rectangle is 4.
The length is 4 times the width = 4 × 4 = 16